In the given radioactive decay if the mass number and atomic number of D2 are 176 and 71 respectively.What is the mass number and atomic number of D? D----->D1------->D2 Bita alpha particle

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In the given radioactive decay if the mass number and atomic number of D2 are 176 and 71 respectively.What is the mass number and atomic number of D? D----->D1------->D2 Bita alpha particle

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Answer 1 · 2018-03-01T06:26:06

Well,though not clearly mentioned,considering,the reaction to be,

$D ------> D_1 + beta ------> D_2+alpha$

Given, mass number of $D_2$ is $176$ , now as $D_2$ has been formed from $D_1$ due to $alpha$ emission,mass number of $D_1$ must be $(176+4)-180$ and similarly atomic number should be $71+2=73$ (as, alpha particle has mass number $4$ and atomic number $2$ )

So, we can complete the $2nd$ half of the reaction,

$""_73^180 D_2 -------> ""_71^176 D_3 + ""_2^4 He$

Similarly, we can say, there will be no change in mass number of $D$ as,beta particle has mass number of $0$ as beta emission is expressed as, $""_(-1)^ 0 beta$ ,So its atomic number must decrease by $1$ i.e $72$

So,the whole reaction becomes,

$""_72^180 D ---->""_73^180 D_2 + ""_-1^0 beta -------> ""_71^176 D_3 + ""_2^4 He$

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In the given radioactive decay if the mass number and atomic number of D2 are 176 and 71 respectively.What is the mass number and atomic number of D? D----->D1------->D2 Bita alpha particle

1 Answer

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