In the equation #x+y=5#, the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

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In the equation #x+y=5#, the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

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Answer 1 · 2017-04-08T19:41:10

#y ∈ {0,1,2}#

Explanation:

If #2< x <6# , it means that #x ∈ {3,4,5}#.

For x = 3
#3+y=5 =>y = 2#
For x = 4
#4+y=5 =>y = 1#
For x = 5
#5+y=5 =>y = 0#

Therefore #y ∈ {0,1,2}#

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In the equation #x+y=5#, the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

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