In the equation #Al_2(SO_4)_3 + 6NaOH -> 2Al(OH)_3 + 3Na_2SO_4#, what is the mole ratio of #NaOH# to #Al(OH)_3#?
1 Answer
May 28, 2016
3:1
Explanation:
The balanced equation will tell the stoichiometric ratio of reactants and products. Here in the balanced equation the coefficient before
So the required mole ratio is 6:2=3:1