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In the complete combustion of 454.0g of liquid butane (#C_4H_10#) what mass of water will be produced?

1 Answer

Dec 28, 2016

Approx. #700*g# of water are produced.

Explanation:

We need (i) a stoichiometrically balanced equation:

#C_4H_10(g) + 13/2O_2(g)rarr4CO_2(g) + 5H_2O(l)#

And thus 5 equiv of water are produced per equiv of butane.

And (ii) we need the equivalent quantity of gas burnt:

#"Moles of butane"# #=# #(454*g)/(58.12*g*mol^-1)=7.81*mol#

And thus #7.81*molxx5xx18.01*g*mol^-1=??g#

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