If you need to prepare 1.5 L of a 1.5 M solution of nitric acid, how many milliliters of 9.0 M nitric acid will you have to dilute to 1.5 L?

1 Answer
anor277
Jan 8, 2018

Well, we must remember to add acid to water....we need #250*mL# of the starting acid.

Explanation:

We want a solution whose volume is #1.50*L#, and whose concentration is #1.50*mol*L^-1#....

And this represents a molar quantity of #1.50*Lxx1.50*mol*L^-1=2.25*mol# with respect to nitric acid...

We have #9.0*mol*L^-1# nitric available.....and so we take the quotient....

#(2.25*mol)/(9.0*mol*L^-1)xx1000*mL*L^-1-=250*mL#...

And so you add #250*mL# nitric acid to #1250*mL# of distilled water.

We remember that if you spit in acid, it spits back.

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