# If you measure 50 mL of cooking oil and the cooking oil has a mass of 43g, what is the density of the oil?

Jul 5, 2018

A little bit less than $1 \cdot g \cdot m {L}^{-} 1$...

#### Explanation:

${\rho}_{\text{density}}$ is given by the quotient....

$\rho = \text{mass"/"volume}$...and clearly has associated units of $g \cdot m {L}^{-} 1$.

Here we take the quotient rho=(43*g)/(50*mL)-=??*g*mL^-1..

And so would the oil float on water? Why or why not? And if you do not know the answer, this is an easy answer to address in the kitchen. Drop a bit of oil in a glass of water. Does the oil float? I dunno, I have not done the experiment recently....

Jul 6, 2018

$0.86$ grams per milliliter

#### Explanation:

Density is given by the equation:

$\rho = \frac{m}{V}$

where:

• $\rho$ is the density of the substance

• $m$ is the mass of the substance

• $V$ is the volume of the substance

So, we get:

$\rho = \left(43 \setminus \text{g")/(50 \ "mL}\right)$

$= 0.86 \setminus \text{g/mL}$