If x is inversely proportional to y, and x = 60 when y = 0.5, how do you find x when y = 12?

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Answer 1 · 2016-03-31T16:02:54

$y=30/x$

At $y=12"; "x= 2 1/2 -= 5/2$

Let $k$ be a constant. Then:

$y=kxx1/x = k/x$

It is given that:

$y=k/x" "->" "0.5=k/60$

Multiply both sides by 60 giving

$(0.5xx60) = kxx (60/60)$

But $60/60=1" and "0.5xx60=30$

$=>k=30$

So the relationship is: $y=30/x$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~
For $y=12$ we have

$12=30/x$

$x=30/12 = 2 6/12 -> 2 1/2$