If we were colliding a Ball (182.20 g Mass), at 100% speed (1.94 m/s), into a tennis ball of the same size, but half the mass of the primary ball, what could we determine about the motion and energy of the tennis ball after the collision?

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Answer 1 · 2018-06-14T13:32:39

$V= 1.29ms¯¹$

$"Energy of tennis ball" = 6.9381 xx 10^-3J$

$"Mass of ball" = M_1 = 0.1822kg$

$"Mass of tennis is half of Mass of ball"$

Therefore;

$"Mass of tennis" = M_2 = 0.0911kg$

$"Velocity of ball" = U_1 = 1.94ms^-1$

$"Velocity of tennis" = U_2 = 0$

Recall, since its inelastic collision..

$M_1 U_1 + M_2 U_2 = (M_1 + M_2)V$

Plugging the values into the equation..

$0.1822 xx 1.94 = (0.1822 + 0.0911)V$

$V = 0.3535/0.2733$

$V= 1.29ms¯¹$

Then energy of tennis ball..

Using;

$K.E = 1/2mv^2$

Energy of tennis ball $= 1/2$ mass of tennis ball $xx v^2$

$"Energy of tennis ball" = (1.672 xx (0.0911)^2)/ 2$

$"Energy of tennis ball" = (1.672 xx 0.00829921)/ 2$

$"Energy of tennis ball" = 0.01387627912/ 2$

$"Energy of tennis ball" = 6.9381 xx 10^-3J$