If there is a loss of #5.63 x 10^-7# kg of mass in a nuclear reaction, how many Joules of energy would be released?

Question

Recall that #c = 3x10^8 m/s#

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Answer 1 · 2016-09-14T15:24:41

Well, #E=mc^2#, or so the physicists assure us.

Thus, #E=5.63xx10^-7kgxx(3xx10^8*m*s^-1)^2#

#=# #5.63xx10^-7kgxx9xx10^16*m^2*s^-2#

And it is a fact (the which I would check!) that #1*J# #=# #1*kg*m^2*s^-2#, which are the units we got in the answer.

So we have approx. #50xx10^9*J# #=# #50xx10^3*MJ#