If the pressure on a gas sample is tripled and absolute temperature is quadrupled, by what factor will the volume of the sample change?

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If the pressure on a gas sample is tripled and absolute temperature is quadrupled, by what factor will the volume of the sample change?

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Answer 1 · 2016-11-27T12:54:02

$V_{2} = \frac{4}{3}$ $V_2=4/3$

Explanation:

The relationship between pressure, volume, and temperature can be expressed as:

$\frac{P V}{T}$ $(PV)/T$

and we can compare one state to another by this expression:

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1=(P_2V_2)/T_2$

In this case, we can say that $P_{1}, V_{1}, T_{1}$ $P_1, V_1, T_1$ are all equal to 1 and have the pressure triple so that $P_{2} = 3$ $P_2=3$ and the temperature quadruple so that $T_{2} = 4$ $T_2=4$ and see what it is that $V_{2}$ $V_2$ will equal:

$\frac{(1) (1)}{1} = \frac{(3) V_{2}}{4}$ $((1)(1))/1=((3)V_2)/4$

$1 = \frac{3}{4} V_{2}$ $1=3/4V_2$

$(1) \frac{4}{3} = (\frac{3}{4}) (V_{2}) \frac{4}{3}$ $(1)color(red)(4/3)=(3/4)(V_2)color(red)(4/3)$

$V_{2} = \frac{4}{3}$ $V_2=4/3$

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If the pressure on a gas sample is tripled and absolute temperature is quadrupled, by what factor will the volume of the sample change?

1 Answer

Explanation:

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