If the length of a $63 c m$ $63 cm$ spring increases to $98 c m$ $98 cm$ when a $15 k g$ $15 kg$ weight is hanging from it, what is the spring's constant?

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If the length of a $63 c m$ $63 cm$ spring increases to $98 c m$ $98 cm$ when a $15 k g$ $15 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2018-05-14T12:31:02

$420$ $420$ newtons per meter

Explanation:

We use Hooke's law, which states that,

$F = k x$ $F=kx$

where:

$F$ $F$ is the force exerted on the spring in newtons

$k$ $k$ is the spring constant, usually in newtons per meter

$x$ $x$ is the extension of the spring in meters

Here:

$F=15 \ "kg"*9.8 \ "m/s"^2=147 \ "N"$

$x=(98 \ "cm"-63 \ "cm")*(1 \ "m")/(100 \ "cm")=0.35 \ "m"$

$:.x=F/k=(147 \ "N")/(0.35 \ "m")$

$=420 \ "N/m"$

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If the length of a $63 c m$ $63 cm$ spring increases to $98 c m$ $98 cm$ when a $15 k g$ $15 kg$ weight is hanging from it, what is the spring's constant?

1 Answer

Explanation:

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Humanities

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If the length of a 63 cm63cm63 cm spring increases to 98 cm98cm98 cm when a 15 kg15kg15 kg weight is hanging from it, what is the spring's constant?

1 Answer

Explanation:

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If the length of a $63 c m$ $63 cm$ spring increases to $98 c m$ $98 cm$ when a $15 k g$ $15 kg$ weight is hanging from it, what is the spring's constant?