If the length of a $53 cm$ spring increases to $87 cm$ when a $1 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2017-07-21T12:57:20

28.8 N/m

$Δx = 87cm - 53cm$

$Δx = 34cm$

$F = mg$

$F = 1kg * 9.8m/s^2$

$F = 9.8N$

$F = k * Δx$

$k = F / (Δx)$

$k = (9.8N) / (34 cm)$

$k = 0.288 N/(cm)$

$k = 28.8 N/m$

If the length of a 53 cm53 cm spring increases to 87 cm87 cm when a 1 kg1 kg weight is hanging from it, what is the spring's constant?