If the length of a $49 cm$ spring increases to $93 cm$ when a $5 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-02-04T19:13:48

$K=111,477 N/m$

$Delta x=93-49=44 cm=0,44 m$
$G=m*g=5*9,81=49,05 N$
$G=K* Delta x$
$49,05=K*0,44$
$K=(49,05)/(0,44)$
$K=111,477 N/m$

If the length of a 49 cm49 cm spring increases to 93 cm93 cm when a 5 kg5 kg weight is hanging from it, what is the spring's constant?