If the length of a $47$ $cm$ spring increases to $89$ $cm$ when a $2$ $kg$ weight is hanging from it, what is the spring's constant?

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If the length of a $47$ $cm$ spring increases to $89$ $cm$ when a $2$ $kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-03-21T06:10:57

We should work in SI units, so the stretch is $0.89-0.47=0.42$ $m$ . Then we know the weight force of a $2$ $kg$ mass is $19.6$ $N$ and $F=kx$ , and can rearrange to give: $k=F/x=19.6/0.42=46.7$ $Nm^-1 or kgs^-2$ .

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If the length of a $47$ $cm$ spring increases to $89$ $cm$ when a $2$ $kg$ weight is hanging from it, what is the spring's constant?

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