If the length of a $47 cm$ spring increases to $57 cm$ when a $8 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2017-06-15T16:51:38

The spring constant is $=784kgs^-2$

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The force is $F=mg=8g N$

The extension is $x=0.57-0.47=0.1m$

The spring constant is

$k=F/e=(8g)/0.1=784kgs^-2$

If the length of a 47 cm47 cm spring increases to 57 cm57 cm when a 8 kg8 kg weight is hanging from it, what is the spring's constant?