If the length of a $46 c m$ $46 cm$ spring increases to $57 c m$ $57 cm$ when a $8 k g$ $8 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2018-03-13T16:53:00

$713 N/m$ $"713 N/m"$

$F = kDeltax$

$k = F/(Deltax) = (mg)/(Deltax) = ("8 kg × 9.8 m/s"^2)/("0.57 m - 0.46 m") = "713 N/m"$

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