If the length of a $44 cm$ spring increases to $58 cm$ when a $5 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-02-04T14:13:56

$K=(49,05)/(0,14)=350,357142857 N/m$

$58-44=14 cm$
$Delta x=14* 10^-2=0,14 meters$
$F=K*Delta x$
$5*9,81=K*0,14$
$49,05=K*0,14$
$K=(49,05)/(0,14)=350,357142857 N/m$

If the length of a 44 cm44 cm spring increases to 58 cm58 cm when a 5 kg5 kg weight is hanging from it, what is the spring's constant?