If the length of a $37 cm$ spring increases to $77 cm$ when a $3 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-02-23T19:33:19

$73.5N//m$

From Hooke's Law, $F=kx$

$therefore k=F/x$

$=(3xx9.8)/(0.77-0.37)$

$=73.5N//m$ .

If the length of a 37 cm37 cm spring increases to 77 cm77 cm when a 3 kg3 kg weight is hanging from it, what is the spring's constant?