If the length of a $35 cm$ spring increases to $73 cm$ when a $3 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2015-12-13T18:15:07

The spring constant will be $-3 N/m$

Given Data:

$Displacement (x) = 73 cm - 35 cm = 38 cm$
$= 38 * 10^-3 m$
$x= 0.38 m$

We've just done this to get it into the SI units or MKS system.

Force (F) $= m*a = 3 * 0.38$
$F = 1.14 N$

Spring Constant (k) = ?

We know:

Spring Constant (k) $= - F/x$

$k = -1.14/0.38$

$k = -3$

This is our final answer.

The trick here and most of these types of questions, the answer will be the mass we multiplying in the force.

If the length of a 35 cm35 cm spring increases to 73 cm73 cm when a 3 kg3 kg weight is hanging from it, what is the spring's constant?