If the length of a $32 c m$ $32 cm$ spring increases to $71 c m$ $71 cm$ when a $4 k g$ $4 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-02-18T14:37:24

$k ≅ 100, 62 \frac{N}{m}$ $k~=100,62 N/m$

$Delta x=71-32=39 " cm"=0,39" m"$
$G=m*g=4*9,81=39,24N$
$G=k*Delta x$
$39,24=k* 0,39$
$k~=100,62 N/m$

If the length of a 32 cm32cm32 cm spring increases to 71 cm71cm71 cm when a 4 kg4kg4 kg weight is hanging from it, what is the spring's constant?