If the length of a $31 cm$ spring increases to $53 cm$ when a $4 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2018-03-13T17:12:03

$"178 N/m"$

$F = kDeltax$

$k = F/(Deltax) = (mg)/(Deltax) = ("4 kg × 9.8 m/s"^2)/("0.53 m - 0.31 m") = "178 N/m"$

If the length of a 31 cm31 cm spring increases to 53 cm53 cm when a 4 kg4 kg weight is hanging from it, what is the spring's constant?