If the length of a $29 cm$ spring increases to $47 cm$ when a $15 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-03-24T14:46:14

$=833.33Nm^-1$

$F=kx$
force $F=mg=15xx10N=150N$
$g =10 ms^-2$
Increase in length $l=(47-29)cm=18cm=0.18m$
force constant $k=F/x=150/0.18N/m=833.33Nm^-1$

If the length of a 29 cm29 cm spring increases to 47 cm47 cm when a 15 kg15 kg weight is hanging from it, what is the spring's constant?