If the length of a $27 c m$ $27 cm$ spring increases to $65 c m$ $65 cm$ when a $4 k g$ $4 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-04-24T18:25:02

$103.158 N / m$ $103.158N//m$

From Hooke's Law, $F = k x$ $F=kx$ .

$therefore k=F/x$

$=((4xx9.8)N)/((0.65-0.27)m$

$=103.158N//m$

If the length of a 27 cm27cm27 cm spring increases to 65 cm65cm65 cm when a 4 kg4kg4 kg weight is hanging from it, what is the spring's constant?