If the length of a $24 c m$ $24 cm$ spring increases to $92 c m$ $92 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

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If the length of a $24 c m$ $24 cm$ spring increases to $92 c m$ $92 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-02-13T22:22:35

$k ≅ 72, 132 \frac{N}{m}$ $k~=72,132N/m$

Explanation:

$Delta x=92-24=68 cm=0,68m$
$"amount of compressing of spring"$
$G=m*g$
$"weight of object"$
$G=5*9,81=49.05N$
$F=k*Delta x$
$49,05=k*0,68$
$k~=72,132N/m$

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If the length of a $24 c m$ $24 cm$ spring increases to $92 c m$ $92 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

1 Answer

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If the length of a 24 cm24cm24 cm spring increases to 92 cm92cm92 cm when a 5 kg5kg5 kg weight is hanging from it, what is the spring's constant?

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If the length of a $24 c m$ $24 cm$ spring increases to $92 c m$ $92 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?