If the length of a 23 cm spring increases to 53 cm when a 10 kg weight is hanging from it, what is the spring's constant?

1 Answer
Feb 17, 2016

k=327 N/m

Explanation:

"amount of changing of length of spring"

Delta x=53-23=30 cm=0,3m

"Weight of object is :"G=m*g

G=10*9,81=98,1 N

G=k* Delta x

98,1=k*0,3

k=(98,1)/(0,3)

k=327 N/m