If the length of a $19 cm$ spring increases to $54 cm$ when a $4 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2017-10-27T20:54:11

The spring constant is 112 N/m.

Spring constant it typically given in units of N/m, so I will convert the spring lengths to m. 19 cm = 0.19 m & 54 cm = 0.54 m

The weight of that 4 kg mass is $m*g = 4 kg*9.8 m/s^2 = 39.2 N$ .
The amount of stretch that the weight caused was
$0.54 m - 0.19 m = 0.35 m$

Therefore the spring constant is $(39.2 N)/(0.35 m) = 112 N/m$

I hope this helps,
Steve

If the length of a 19 cm19 cm spring increases to 54 cm54 cm when a 4 kg4 kg weight is hanging from it, what is the spring's constant?