If the length of a $15 cm$ spring increases to $28 cm$ when a $2 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-04-15T08:54:02

$k=150,92" N/m"$

$m=2kg$
$g=9,81 N/(kg)$

$G=m*g=2*9,81=19,62 N" Force acting to spring"$
$k:"spring constant"$
$Delta x=28-15=13 cm=0,13 m$
$F=G=k*Delta x$

$19,62=k*0,13$

$k=(19,62)/(0,13)$

$k=150,92" N/m"$

If the length of a 15 cm15 cm spring increases to 28 cm28 cm when a 2 kg2 kg weight is hanging from it, what is the spring's constant?