If the angle $10$ $10$ is in standard position, which quadrant does it terminate?

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Answer 1 · 2018-04-27T00:03:47

10 radians is about 6.4 ninety degree angles, which puts it comfortably in the third quadrant.

Not clear if this is $10$ $10$ radians or $10^{\circ} .$ $10 ^circ.$ Let's do both.

$10^{\circ}$ $10^circ$ is obviously in the first quadrant, no need to belabor that..

$10$ $10$ radians. A quadrant is $90^{\circ}$ $90^circ$ or $\frac{π}{2} .$ $\pi/2.$ Let's count quadrants:

$\frac{10}{\frac{π}{2}} \approx 6.4$ $10 / (\pi/2) approx 6.4$ .

0-1 means first quadrant, 1-2 second, 2-3, third, 3-4 fourth, 4-5 first, 5-6, second, 6-7 third, bingo.

If the angle 101010 is in standard position, which quadrant does it terminate?