If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of #8.0 x 10^10 s^(-1)#, what is the rate constant for this reaction at 298 K?
1 Answer
Jan 26, 2018
Explanation:
Rate constant can be calculated from Arrhenius equation
#k = A xx e^(-E_a/(RT))#
Where,
k = Rate constant
A = Frequency factor
#E_a# = Activation energyR = Gas constant
T = Absolute Temperature