If #sin theta = 1/4, then cos(90degrees - theta) =?

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If #sin theta = 1/4, then cos(90degrees - theta) =?

Explanation please?

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Answer 1 · 2018-01-29T12:52:45

$cos (90^{\circ} - θ) = \frac{1}{4}$ $cos(90^@-theta)=1/4$

Explanation:

For all angles $A$ $A$ , $cos (90^{\circ} - A) = sin A$ $cos(90^@-A)=sinA$

Hence $cos (90^{\circ} - θ) = sin θ = \frac{1}{4}$ $cos(90^@-theta)=sintheta=1/4$

Answer 2 · 2018-01-29T13:44:26

$\frac{1}{4}$ $1/4$

Explanation:

$using the trigonometric identity$ $"using the "color(blue)"trigonometric identity"$

$∙ x {cos (90 - θ)}^{\circ} = sin θ$ $•color(white)(x)cos(90-theta)^@=sintheta$

$\Rightarrow cos (90 - θ) = sin θ = \frac{1}{4}$ $rArrcos(90-theta)=sintheta=1/4$

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If #sin theta = 1/4, then cos(90degrees - theta) =?

Explanation please?

2 Answers

Explanation:

Explanation:

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