If #sin theta = 1/4, then cos(90degrees - theta) =?

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Explanation please?

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Answer 1 · 2018-01-29T12:52:45

#cos(90^@-theta)=1/4#

For all angles #A#, #cos(90^@-A)=sinA#

Hence #cos(90^@-theta)=sintheta=1/4#

Answer 2 · 2018-01-29T13:44:26

#1/4#

#"using the "color(blue)"trigonometric identity"#

#•color(white)(x)cos(90-theta)^@=sintheta#

#rArrcos(90-theta)=sintheta=1/4#