If sides A and B of a triangle have lengths of 5 and 2 respectively, and the angle between them is $(5pi)/8$ , then what is the area of the triangle?

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Answer 1 · 2018-05-16T07:11:43

$A=color(red)(4.61939766256 " square units"$

Use $Area=1/2 xx a xx b xx sin C$

$A=cancel(color(red)(1/2)) xx 5 xx cancel(color(red)(2)) xx sin ((5pi)/8)$

$A=color(red)(4.61939766256 " sq units"$

Answer 2 · 2018-06-18T01:53:26

$"Area of a " Delta, A_t = (1/2) a * b * sin C$

$"Given : a = 5, b = 2, hat C = (5pi) / 8$

$:. A_t =cancel (1/2) * 5 * cancel2 * sin ((5pi)/8)$

$A_t = 5 sin ((5pi) / 8) = 4.62 " sq units"$

If sides A and B of a triangle have lengths of 5 and 2 respectively, and the angle between them is (5pi)/8(5pi)/8, then what is the area of the triangle?