If sides A and B of a triangle have lengths of 1 and 6 respectively, and the angle between them is $(7pi)/8$ , then what is the area of the triangle?

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Answer 1 · 2016-08-15T16:43:25

$"Area of the triangle"=1/2ABsin(7pi/8)$

$=1/2*1*6*sin(pi-pi/8)$

$=3*sin(pi/8)=1.148squnit$

If sides A and B of a triangle have lengths of 1 and 6 respectively, and the angle between them is (7pi)/8(7pi)/8, then what is the area of the triangle?