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If it takes 25 mL of 0.05 M #HCl# to neutralize 345 mL of #NaOH# solution, what is the concentration of the #NaOH# solution?

1 Answer

Jun 27, 2016

#[NaOH]~=4xx10^-3*mol*L^-1#

Explanation:

#NaOH(aq) + HCl(aq) rarr NaCl(aq) + H_2O(l)#

There is 1:1 equivalence between acid and base.

Thus #[NaOH]# #=# #(25xx10^-3Lxx0.05*mol*L^-1)/(345xx10^-3L)#

#=# #??*mol*L^-1#

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