If I wanted to find the interior angle sum of a polygon with 102 sides, what would it be?

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Answer 1 · 2016-02-01T11:33:47

$18000^@$

we know,
the sum of the interior angels of a polygon is,

$s=180^@(n-2)$

for the polygon with 102 sides,

$s=180^@(102-2)$

$=180^@xx100$

$=18000^@$

Answer 2 · 2016-04-13T05:58:12

$18000^circ$

Remember the formula

$color(brown)(a=(n-2)180^circ$

Where

$color(blue)(a="sum of interior angles"$

$color(blue)(n="number of sides of the polygon"$

Now, we need to find $a$

$rarra=(102-2)180^circ$

$rarra=(100)180^circ$

$color(green)(rArra=18000^circ$