If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature of 200. K, and then I raise the pressure to 14.0 atm and increase the temperature to 300. K, what is the new volume of the gas?

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Answer 1 · 2016-10-11T03:06:02

The two actions work against each other.

Raising the temperature will increase the volume:
#V_T=(300K)/(200K)xx24.0L=36.0L#

Increasing the pressure will decrease the volume:
#V_(T,p)=(10.0atm)/(14.0atm)xx36.0L~~25.7L#

It doesn't matter if you first do the one and then the other, or the other way around, or both simultaneously