If $g(x)=x^2+5x+4$ and $f(x)=x-2$ , how do you find g(f(-2))?

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Answer 1 · 2016-11-14T23:07:36

$g(f(-2)) = 0$

This means to insert $f(x)$ into $g(x)$ and then evaluate when $x= -2$ .

$g(f(x)) = (x- 2)^2 + 5(x - 2) + 4$

$g(f(x)) = x^2 - 4x + 4 + 5x -10 + 4$

$g(f(x)) = x^2 + x - 2$

$g(f(x)) = (x + 2)(x- 1)$

$g(f(-2)) = (-2 + 2)(-2 - 1)$

$g(f(-2)) = 0$

Hopefully this helps!

If g(x)=x^2+5x+4g(x)=x^2+5x+4 and f(x)=x-2f(x)=x-2, how do you find g(f(-2))?