If $f(x)=x^2-81$ and $g(x)=(x-9)^-1(x+9)$ , how do you find $g(x)timesf(x)$ ?

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Answer 1 · 2016-12-12T22:02:40

$g(x) xx f(x) = ( x + 9)^2$

$g(x) xx f(x) = x^2 - 81 xx (x + 9)/(x - 9)$

$= ((x + 9)(x - 9)(x+ 9))/(x- 9)$

$=(x + 9)(x + 9)$

$=(x + 9)^2$

Hopefully this helps!

If f(x)=x^2-81f(x)=x^2-81 and g(x)=(x-9)^-1(x+9)g(x)=(x-9)^-1(x+9), how do you find g(x)timesf(x)g(x)timesf(x)?