If f(x)=x^(1/2)-xf(x)=x12x and g(x)=2x^3-x^(1/2)-xg(x)=2x3x12x, how do you find f(x)-g(x)f(x)g(x)?

1 Answer
Oct 16, 2017

f(x) - g(x) = 2x^(1/2) - 2x^3f(x)g(x)=2x122x3

Explanation:

Just do the arithmetic:

f(x) - g(x) = x^(1/2) - x - (2x^3 - x^(1/2) - x)f(x)g(x)=x12x(2x3x12x)

f(x) - g(x) = x^(1/2)- x - 2x^3 + x^(1/2) + xf(x)g(x)=x12x2x3+x12+x

f(x) - g(x) = 2x^(1/2) - 2x^3f(x)g(x)=2x122x3

Hopefully this helps!