If f(x)=x^(1/2)-xf(x)=x12−x and g(x)=2x^3-x^(1/2)-xg(x)=2x3−x12−x, how do you find f(x)-g(x)f(x)−g(x)?
1 Answer
Oct 16, 2017
Explanation:
Just do the arithmetic:
f(x) - g(x) = x^(1/2) - x - (2x^3 - x^(1/2) - x)f(x)−g(x)=x12−x−(2x3−x12−x)
f(x) - g(x) = x^(1/2)- x - 2x^3 + x^(1/2) + xf(x)−g(x)=x12−x−2x3+x12+x
f(x) - g(x) = 2x^(1/2) - 2x^3f(x)−g(x)=2x12−2x3
Hopefully this helps!