If #f(x)=x^(1/2)-x# and #g(x)=2x^3-x^(1/2)-x#, how do you find #f(x)-g(x)#?
1 Answer
Oct 16, 2017
Explanation:
Just do the arithmetic:
#f(x) - g(x) = x^(1/2) - x - (2x^3 - x^(1/2) - x)#
#f(x) - g(x) = x^(1/2)- x - 2x^3 + x^(1/2) + x#
#f(x) - g(x) = 2x^(1/2) - 2x^3#
Hopefully this helps!
