If $f(x)=x^(1/2)-x$ and $g(x)=2x^3-x^(1/2)-x$ , how do you find $f(x)-g(x)$ ?

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Answer 1 · 2017-10-16T01:05:51

$f(x) - g(x) = 2x^(1/2) - 2x^3$

Just do the arithmetic:

$f(x) - g(x) = x^(1/2) - x - (2x^3 - x^(1/2) - x)$

$f(x) - g(x) = x^(1/2)- x - 2x^3 + x^(1/2) + x$

$f(x) - g(x) = 2x^(1/2) - 2x^3$

Hopefully this helps!

If f(x)=x^(1/2)-xf(x)=x^(1/2)-x and g(x)=2x^3-x^(1/2)-xg(x)=2x^3-x^(1/2)-x, how do you find f(x)-g(x)f(x)-g(x)?