If $f (x) = ∣ ∣ x^{2} - 3 ∣ ∣$ $f(x)=abs(x^2-3)$ , how do you find f(2)?

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Answer 1 · 2017-01-10T21:25:07

Replace the $x$ $x$ with the given value of 2, then follow normal order of operations.

#f(2) = |2^2 - 3| = |4-3| = |1|

Since the argument in the absolute value bars is a positive number, they serve no real purpose, and can be removed.

(Had the argument in the bars been -1, the answer would also have been 1, since the absolute value always returns a positive result.)

If f(x)=abs(x^2-3)f(x)=∣∣x2−3∣∣f(x)=abs(x^2-3), how do you find f(2)?