If #f(x)=-2x+7# and #g(x)=x+2#, what is #f * g#?
1 Answer
Oct 1, 2017
Explanation:
#(f*g)(x)=f(x)xxg(x)#
#color(white)((f*g)(x))=(-2x+7)(x+2)#
#"expand using FOIL"#
#(-2x+7)(x+2)=-2x^2-4x+7x+14#
#rArr(f*g)(x)=-2x^2+3x+14#