If f(x) = 2x^2 - 4x +2, how would you find the equation of the tangent of the line of f(x) at the point (5,32) and the derivative when f'(5) = 16 ?

1 Answer
Ion ยท Somebody N.
Nov 10, 2017

y= 16x + 48

Explanation:

Input the point (5, 32) into the equation of y_2-y_1 = m(x_2-x_1).

The value of m being the value of 16.

y - 32= 16 (x-5)

y = 16x - 80 +32

y= 16x -48

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