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If f(x) = 2x^2 - 4x +2, how would you find the equation of the tangent of the line of f(x) at the point (5,32) and the derivative when f'(5) = 16 ?

1 Answer

Ion · Somebody N.

Nov 10, 2017

$y = 16 x + 48$ $y= 16x + 48$

Explanation:

Input the point $(5, 32)$ $(5, 32)$ into the equation of $y_{2} - y_{1} = m (x_{2} - x_{1})$ $y_2-y_1 = m(x_2-x_1)$ .

The value of $m$ $m$ being the value of 16.

$y - 32 = 16 (x - 5)$ $y - 32= 16 (x-5)$

$y = 16 x - 80 + 32$ $y = 16x - 80 +32$

$y = 16 x - 48$ $y= 16x -48$

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