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If #cos theta =7/8,#evaluate#{(1+sin theta)(1-sin theta)]/[(1+cos theta)(1-cos theta)] #?

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Aug 17, 2017

#{(1+sin theta)(1-sin theta)]/[(1+cos theta)(1-cos theta)] #

#=(1-sin^2theta)/(1-cos^2theta)#

#=(cos^2theta)/(1-cos^2theta) #

#=(7/8)^2/(1-(7/8)^2) #

#=(7/8)^2/((8^2-7^2)/8^2) #

#=49/15#

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