If an object is moving at #8 m/s# over a surface with a kinetic friction coefficient of #u_k=9 /g#, how far will the object continue to move?

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Answer 1 · 2018-05-05T06:21:35

The distance is #=3.56m#

The coeffcient of kinetic friction is #mu_k=9/g#

#mu_k=F_r/N#

Let the mass of the object be #=m kg#

Then,

The normal reaction is #N=mg N#

The frictional force is

#F_r=mu_kN=mu_kmg=9/g*mg=9mN#

#F=ma#

The acceleration is #a=F/m=F_r/m=-9m/m=-9ms^-2#

The initial velocity is #u=8ms^-1#

Apply the equation of motion

#v^2=u^2+2as#

The final velocity #v=0#

#0=64-2xx9xxs#

The distance is

#s=64/18=3.56m#