If an object is moving at #6 m/s# over a surface with a kinetic friction coefficient of #u_k=24 /g#, how far will the object continue to move?

1 Answer
ali ergin
Mar 27, 2016

#"Object has a kinetic energy : "E_k=1/2*m*v^2#
#E_k:"The kinetic energy of object"#
#m:"mass of object"#
#v:" velocity of object"#
#"The kinetic energy of object is turned to the heat energy by "#
#"the friction force."#
#E_k=F_f*Delta x#
#1/2*cancel(m)*v^2=u_k*cancel(m)*g*Delta x#
#Delta x=v^2/(2*u_k*g)#

#Delta x=6^2/(((2*24)/cancel(g))*cancel(g))#

#Delta x=36/48#

#Delta x=3/4 " m"#

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