If an equilateral triangle has a height of $4.7sqrt3$ and base of 9.4 cm, what is its area?

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Answer 1 · 2015-06-27T13:53:14

$1/2 xx base xx height = 4.7^2sqrt(3)$ $cm^2$

$= 22.09sqrt(3)$ $cm^2$

$~= 38.261$ $cm^2$

As with all triangles, the area is equal to half of the base multiplied by the height.

If an equilateral triangle has a height of 4.7sqrt34.7sqrt3 and base of 9.4 cm, what is its area?