If a velocity-time graph (starting at (0,0) and ending at (10,10) has a positive linear trend, then what would the distance-time and acceleration-time graphs look like?

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Answer 1 · 2015-09-02T21:56:16

They would look like this:

MF docs

For the 1st graph you can see that $(DeltaV)/(Deltat)=10/10=1$

This gives a straight line of gradient 1 meaning constant acceleration.

This gives the 3rd graph of acceleration / time to be a horizontal line of gradient zero.

The 2nd graph of distance / time is of the form :

$s=1/2at^2$

This gives you the parabola.