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If a spring has a constant of #6 (kg)/s^2#, how much work will it take to extend the spring by #43 cm #?

1 Answer

Feb 15, 2016

#W=E_p=0,5547 J#

Explanation:

#"It has the potential energy ,if spring extends"#
#W=E_p=1/2*k*Delta x^2#
#W=E_p=1/2*6*(0,43)^2#
#43 cm=0,43 m#
#W=E_p=3*0,1849#
#W=E_p=0,5547 J#

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