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If a spring has a constant of #4 (kg)/s^2#, how much work will it take to extend the spring by #94 cm #?

1 Answer

Jul 25, 2018

The work is #=1.77J#

Explanation:

The work done is equal to the the potential energy stored in the spring

#W=1/2kx^2#

The spring constant is #k=4kgs^-2#

The extension is #x=0.94m#

The work is

#W=1/2*4*0.94^2=1.77J#

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