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If a projectile is shot at an angle of #(pi)/8# and at a velocity of #95 m/s#, when will it reach its maximum height?

1 Answer

Mar 5, 2016

#t~=3,71" " s#

Explanation:

enter image source here
#t=v_i*sin alpha/g " elapsed time to maximum height:"#
#t=(95*sin 22,5)/(9,81)#
#t~=3,71" " s#

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