If a projectile is shot at an angle of (pi)/8 and at a velocity of 14 m/s, when will it reach its maximum height?

1 Answer
Feb 9, 2016

h_(max)~=1,463 " m"

Explanation:

h_(max) " of a projectile may be calculated by:"
h_(max)=(v_i^2*sin^2 theta)/(2*g)
theta=pi/8 * 180/pi
theta=22,5 ^o
sin theta=0,382683432365
sin^2 theta=0,146446609409
h_(max)=(14^2*0,14644609409)/(2*9,81)
h_(max)=(196*0,14644609409)/(19,62)
h_(max)~=1,463 " m"